Answer:


The figures are a bit out-dated, sorry, but the numbers are of course still the same when you use the newest MRS to look them up...

BLAST result of the first sequence. Looking in 1isk_bovin, you find all C-s bridged, and 32 has the lowest number of those. 32 in 1isk_bovin corresponds to 12 in our sequence.

The second sequence is a fragment of ther_bacth. In the FT section you find 3 residues (374, 378, 398) binding the Zinc (that is catalitic).

A BLAST run gives you immediately the view that the missing residues are C-terminal. You also see that the protein he cloned is opsr_bovin. And you see there are no other problems because the match is 100%.

But now comes the problem. How many are missing? You cannot see that dfrom the BLAST output, I think. But you see that BLAST gives 337 residues in the aligned bit. Now click on opsr_bovin and scroll to the bottom on the file:

So, the sequence actually has 364 amino acids. 364 - 337 = 27

And now the math: 12+3+27=42. And that, as we all know, is THE answer. The rest of the day we will address the corresponding question...