Answer:


ALMEILAQAARA

Almost all residues come from AMELK, and the few don't (IQR) have Pα >= 1.0 too (0.98 is the same as 1.00...). ELMKIAQLAKRGP HHHHHHHHHHH-- And be aware, the GP at the end is NOT a turn, because a turn is between two things! This GP is just at the end, so it is a loop. SNPAELLQALMKGS --HHHHHHHHHH-- This is a short helix that sits bewteen two short loops (again, loops and not turns). The only non-AMELK residue is Q, and Q has Pα >  1.0. TVEITFKI +-+-+-+- Many VITWYF residues and beautiful alternating phobics (-) abd philics (+) VVICETTWYVEVT +-+-+-+-+-+-+ Strand? + is out; - is in. One T points in, further all is OK. Many VITWYF residues. A few hydrophobics point out but that is allowed. So: Strand! VTITVEGPKITVE -+-+-+TT+-+-+ β-hairpin? + is out; - is in and those are OK. Turn is GP is also OK. So, Hairpin! SRGGEPTRHEAKE ---------HHHH Beginning is a mess (aka loop). End can be helical, but 4 residues seems not much to decide that something might be a helix. So, perhaps the beginning of a helix, but only perhaps. ELLALKLLTVTVT HHHHHHHHSSSSS 1 HHHHHHH-SSSSS 2 HHHHHHHH-SSSS 3 But you normally need HHH-SSS so solution 2 or 3. Look up Chou and Fasman parameters. L is more 'expensive' in a helix than T in a strand. So, solution 3.